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Dance like you got it all figured out (i.imgur.com)

submitted ago by taozero

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[–]dlink 73 points74 points ago

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The best part is that if you know the cos(x) dance you also know the sin(x) dance! All you have to do is hammer-time slide pi/2 to the left.

[–]musicismath 5 points6 points ago

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I prefer to moonwalk 3pi/2 to the right, but to each their own.

[–]alphazero924 3 points4 points ago

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You can't moonwalk sideways. That's just silly.

[–]DivineIntervention 1 point2 points ago

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Maybe you can't.

[–]traal 23 points24 points ago

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x2 + y2, to be implicit "y=" equations like the others, should be ±√(1 - x2 ).

[–]Sticky_Bandit 7 points8 points ago

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Yeah, I was like, equals what?!?!?? What's the radius?!?!?!?

[–]musicismath 3 points4 points ago

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It's the length of your arms divided by 2 pi.

[–][deleted] ago

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[deleted]

[–]explodingfrog 46 points47 points ago

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Mine too. He called it calcisthenics.

[–][deleted] ago

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[deleted]

[–]explodingfrog 16 points17 points ago

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the best part watching people during tests who'd randomly throw their arms into the air to remember what a particular graph looked like.

[–]tallkiller 1 point2 points ago

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did you go to troy?

[–][deleted] ago

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[deleted]

[–]tallkiller 6 points7 points ago

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oh, we did something like that

[–]akdas 5 points6 points ago

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Try doing the sin(1/x).

[–]josephgee 2 points3 points ago*

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Or x!+y!=1

[–]spoolio 1 point2 points ago

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I had to re-type it into WA to get it to work, but that is a damn cool graph.

I also like x!+y!=6, adding an island of sanity to all the negative-factorial weird shit.

EDIT: Or x!+y!=2 -- it's like ellipses being stabbed by asymptotes!

[–]The_Upmachine 14 points15 points ago

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Shouldn't the square root of negative x be negative the square root of x? otherwise its an imaginary dance.

[–]niktay 9 points10 points ago

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It works as long as the graph stays with negative x values. The two negatives cancel out.

[–]diadem 0 points1 point ago

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I came here just to say that. I'm glad this was readily noticed. There may be hope for reddit yet.

edit: though in fairness the square root of positive x would have the same issue for the other side of the number line

[–]GAMEchief -1 points0 points ago

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I agree that the equation is fucked, but negative square root of x would just be an 'upside down' version of square root of x. The graph is more of a 1-sqrt(x) or some such thing, give or take to the 1.

[–]alphazero924 -1 points0 points ago

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No, it's just sqrt -x, x < 0

[–]GAMEchief -1 points0 points ago

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All other graphs in the picture start at x = 0 and increase, ergo that graph does not fit and needs to be adjusted to make it so. Changing the domain is the least intuitive for the reader, least hinted at by the author, and least inventive way to fix the problem here.

[–]alphazero924 0 points1 point ago

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No they don't. All of the other graphs have x=0 as the middle of the dude's body, so it's only slightly offset to our right.

[–]GAMEchief 0 points1 point ago

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Fair enough that x=0 is the middle, but the point still stands.

[–]alphazero924 0 points1 point ago

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But 1-sqrt(x) would be an upside-down sqrt(x) moved up by one. The only equation that gives us sqrt(x) flipped over the vertical axis is sqrt(-x).

[–]GAMEchief 0 points1 point ago

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sqrt(x-domain_start) v. sqrt(domain_start-x)

Essentially the same thing, but without altering the domain. domain_start can be solved by looking at the cos(x) movement, surely. I don't have it open, but it's probably something like pi.

[–]DownvoteMeFuckers -2 points-1 points ago

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You clearly understand nothing of math you dumb, dumb motherfucker.

[–]GAMEchief 1 point2 points ago

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Troll harder?

[–]bubba_lexi 5 points6 points ago

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Nice repost.

[–]artychick2009 1 point2 points ago

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I am so doing this :)

[–]superdude4agze 0 points1 point ago

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Film and post it here.

[–]kriukov 1 point2 points ago

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sin(1/x), please.

[–]alphazero924 1 point2 points ago

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I like to imagine that's a sine wave getting suck into a black hole.

[–]akdas 0 points1 point ago

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That's one of my favorite functions. Continuous and infinitely differentiable in ℝ-{0} but still really crazy near 0.

[–]fas2 1 point2 points ago

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Source missing.

[–]marceriksen 0 points1 point ago

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Definitely a crap dancer here and enjoy every second of it.

[–]Krauti 0 points1 point ago

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I need the feet-equations of these dance-lessons too, please. Otherwise I will look stupid standing still just moving my arms. Anyone can help?

[–]SirSandGoblin 0 points1 point ago

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I am a big fan of this

[–]OhKevin 0 points1 point ago

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I think they tried to divide by zero in that last one.

[–]Bendix 0 points1 point ago

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The repetition of this image in my life this week is getting me annoyed.

[–]soup_sandwich 0 points1 point ago

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oh dear, he fucked up sin/cos. look at the left (our right) arm. i can't trust the rest of these dance moves now...

[–]echosa -1 points0 points ago

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1/x makes me think of Napolean Dynamite...

[–]BobRawrley -1 points0 points ago

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This was taken from a girl who applied to Tufts University's application video. You can find it here.

[–]EpicWolverine -1 points0 points ago

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saw this on vsauce first :D http://www.youtube.com/watch?v=5e65WRAA3T0

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