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Dance Moves [pic] (asset.soup.io)

submitted ago by jh99

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[–]chillorbechilled 38 points39 points ago

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that's how I got through high school calculus! beautiful dance moves indeed.

[–]ozark52 20 points21 points ago

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Our calc teacher had us do these as well. He called 'em matherobics...

[–]mwalker_nz 24 points25 points ago

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Putting the funk back into functions

[–][deleted] 5 points6 points ago

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Putting the sin back into sine

[–][deleted] ago

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[deleted]

[–]thelastbaron 65 points66 points ago

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That dance move is undefined.

[–]Guslikessoda 0 points1 point ago

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the first part of that dance move is to acquire a puppy... the next part is not nice

[–]slyguy183 0 points1 point ago

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You divided by zero on the dance floor? OH SHI-

[–]metaranha 17 points18 points ago

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|x| Steve Holt!

[–]DirtPile 2 points3 points ago

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lol Touch down!

[–]Lizard 15 points16 points ago

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I think the last one is known as "arm waving" and can also be a valid mathematical proof, as long as its done by someone sufficiently intimidating.

[–]legion_pua 1 point2 points ago

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"Here by dragons"

[–]2GuysAaron 31 points32 points ago

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Ha ha! I get it because I know math.

[–]trongable 13 points14 points ago

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It upsets me that the last image is not a complicated function punchline

[–]wauter 0 points1 point ago

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Should have been the Weierstrass function.

[–]nlevend 12 points13 points ago

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The third to last panel is an imaginary number.

Shouldn't it be -SQRT(x)?

[–]FedoraToppedLurker 10 points11 points ago

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Only for x > 0. For x < 0 it is real.

-SQRT(x) would be SQRT(x) flipped over the x axis. Wolfram has a graph.

[–]Nikuhiru 1 point2 points ago

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You do have a valid point; the dance move only represents the real part of the graph.

He should have put sqrt(x2) - would have been a lot easier and could have formed a C! He could be doing the YMCA!

[–]FedoraToppedLurker 0 points1 point ago

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sqrt(x2 ) would be just like the absolute value. You want ±sqrt(x).

[–]nocheckers -2 points-1 points ago

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Actually it doesn't matter if x is >0 or <0 because the number gets squared and then the - is applied. It should be -SQRT(x) like he said because otherwise it's an imaginary number.

[–]binary 1 point2 points ago

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The number is not squared.

[–]nocheckers 2 points3 points ago

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You're right. What was I thinking? Forget everything I said.

[–]prorator 0 points1 point ago

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Using the definition of the square root it is.

For example:

sqrt(4): x2 = 4 (x=2)

but

sqrt(-4): x2 = -4 (x is imaginary)

[–]pignewton 8 points9 points ago*

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Throw your hands in the air, like a graph of x square!

[–]fairestcheetah 6 points7 points ago*

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In a circle (assuming Cartesian coords), x2 + y2 is constant. With the others all solved for y, that one doesn't make any sense.

EDIT: SizzlingStapleCider points out that the image actually is correct - it puzzled me for a bit but it checks out:
r2 = (x - a)2 + (y - b)2 [general equation for a circle]
1/22 = x2 + (y - 1/2)2 [radius 1/2, origin at (0, 1/2)]
1/4 = x2 + y2 - 1y + 1/4 [simplify]
y = x2 + y2

[–]SizzlingStapleCider 3 points4 points ago

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I plugged y = x2 + y2 into a graphing app, and it plotted a circle at (0, 0.5) with a 0.5 radius.

[–]baddox 1 point2 points ago

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Still, it's different from all the others in that it's not the graph of a function.

[–]fairestcheetah 0 points1 point ago

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Oh, wow - OP was right. I have updated my comment.

[–]AcrossTheUniverse 0 points1 point ago

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You have to move your arm like a paraboloid.

[–]seren6ipity 5 points6 points ago

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Cos it's a sin that the root of absolute values is tangent to the circular path we take.

[–]Hello-Ginge 2 points3 points ago

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Slightly relevant occurrence: I opened this while watching Carnivale, and a character said "it's a sin" right as I looked at the first one. Weird.

[–]vwllss 0 points1 point ago

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Yeah but sin(e) is pronounced like "sign"

[–]Hello-Ginge 5 points6 points ago

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Cheers captain patronise, I am aware of that, but it was still bloody weird.

[–]DebtOn 0 points1 point ago

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Oh I thought he was saying 'it's a sign'.

[–]SizzlingStapleCider 0 points1 point ago

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It must mean something.

[–]nocheckers 0 points1 point ago

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That's God talking to you. There is no such thing as coincidence because everything happens for a reason. Let Jesus take the wheel.

[–]Hello-Ginge 0 points1 point ago

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So I should sin more? Will do.

[–]nocheckers 0 points1 point ago

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Let the sin, begin!

[–]Hello-Ginge 0 points1 point ago

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Sinsational!

[–]diadem 1 point2 points ago

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I like how they threw in i in there like it was nothing.

[–]Nubicus_Maximus 1 point2 points ago

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Upboat for being a nerd and an awesome dancer AT THE SAME TIME!!!

[–]Scottzah 2 points3 points ago

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Math dances can even get you into college: http://www.youtube.com/watch?v=CNPXUWsMdIo

[–]BobRawrley 0 points1 point ago

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I wonder which came first, this comic, or that dance. BTW, met that girl when she came to Tufts

[–]arczi 1 point2 points ago

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What's the |x| operator? I'm trying to google it, but the search engine strips the pipes off the query...

[–]TroyDowling 4 points5 points ago

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Absolute value.

|x| = x

|-x| = x

[–]ffn 0 points1 point ago

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Given that x >= 0

[–]TroyDowling 0 points1 point ago

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|-x| = x where x = -3

|-(-3)| = |3| = 3

[–]havk 2 points3 points ago

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In case you're not kidding: http://en.wikipedia.org/wiki/Absolute_value

[–]arczi 3 points4 points ago

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I wasn't. Just couldn't put my finger on it.

[–]fairestcheetah -2 points-1 points ago

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abs(x)

[–]Flex-O 1 point2 points ago

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sin(1/x)

[–]Malkor 0 points1 point ago

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nice

[–]MTGandP 0 points1 point ago

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The last panel was not as good.

[–]jisoukishi 0 points1 point ago

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actually im fairly certain the last one is random(x)....

[–]McDrawrHumperdink 0 points1 point ago

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http://mathworld.wolfram.com/CannabisCurve.html

[–]SizzlingStapleCider 0 points1 point ago

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What about the Egyptian/Heaviside?

[–]jerhinesmith 0 points1 point ago

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Holy shit, I thought I was the only one that did this. I love you.

[–]iswearitsnotme 0 points1 point ago

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You just figured out the formula for voguing.

[–]Eggby 0 points1 point ago

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My dance moves are undifferentiable. Suck it, nerds!

[–]thewaves 0 points1 point ago

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I actually made a choreography to Benny Benassi's Satisfaction using these same moves and presented it to my class. Best assignment of my life!

[–]fuckyou_space 0 points1 point ago

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Any idea the source?

[–]CraziusMikeus 0 points1 point ago

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Demo of some of these moves in action!

[–]_dustinm_ 0 points1 point ago

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imgur mirror (cause it's blocked in WebSense)

[–]brian073 -2 points-1 points ago

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FTFY

[–]Shiranaru -2 points-1 points ago*

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Actually, doing the √(-x) is impossible, because √(-x)=i√(x), which means that your arms would go into the imaginary planes. Also, √(x) should use two arms, pointing in the same direction, because x2 = x = (-x)2 .

[–]Xentreos 1 point2 points ago

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f(x) = sqrt(-x) is perfectly possible without complex numbers. For example, f(-4) = sqrt(- (-4)) = 2.

[–]looeee 0 points1 point ago

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True, but then the result is the same as for √(x). So the diagram is still wrong.

[–]Xentreos 0 points1 point ago

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It's correct in the diagram. It's sqrt(x) reflected over the y axis

[–]looeee 1 point2 points ago

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Actually, you are right! Well done :)

[–]funderbolt -1 points0 points ago

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Beats the heck out of big fish, little fish, cardboard box.

[–]pitman -3 points-2 points ago

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Anything math related makes my head hurts.

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